First of all what are limits ? what are they used for? Why are they the base of all calculus.
When Ms.Hwang Talks about limits i blank out because its like she is speaking another language.
There are simple problems like
f(x)= lim(x►1) (x^2-1)/(x-1)
1.First you foil out (x^2-1)
(x-1)(x+1)/(x-1)
2. Then the (x-1) on top and bottom cancel out and become 1.
(not ZERO)
3. Last you plug in the number that is with the limit to see if the limit exists.
(x+1) = 1+1 = 2
The limit is 2.
Another thing i dont know how to do is foiling out formulas like this
2x^2-5x-3
i was never taught that!!! I think???
so that is about it.
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haha. I can hear your frustration in this post. But that's ok, because now I know.
ReplyDeleteFirst off, what you are talking about is not FOILing, it's called FACTORING. Foiling is multiplying out two binomials. Factoring is taking a polynomial and changing it back into a product. I can teach you how to factor this week. Remind me.
Secondly, consider limits to be like a new function. Kind of like how y=int x was a new function to you guys.
If you see lim (x-->2) f(x), what this limit function is doing is asking you, what is the OUTPUT of f(x) becoming as the INPUT approaches 2. The limit doesn't care about what happens at 2, just right around 2.
I hope this helped. If not, there's always after school this week. I hope you're feeling better Monica!
Well u did solve the first problem, so i dont understand your question on that part?
ReplyDeleteI think of limits like a loophole in a contract. The contract says you cannot do this because there is no output(aka f(x) says soemthing cant exist). However finding a way to get around it (aka peicewise or simplifying) lets you do that action without breaking the contract like lawyers do lol
^_^
i know right!!!!!!!!!!!
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